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  #1  
Old 05-12-2012, 06:04 AM
MadBlaster MadBlaster is offline
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hmm, before I read further, I think we need zero lift drag coefficient for 190 to say that weight is the deciding factor. wiki says 27.87 m² for p47 wing area and 18.30 m² for 190A. Agree with you that denominator (i.e., weight) is almost twice as large for p47 verses 190, but numerator? To keep simple math, assume zero drag coeff=1 for both planes, 190 weighs "1" and p47 weighs "2" (weight on relative basis to each other). Then drag coefficient portion of numerator

-dragcoefficentX(speed)^2/weight

where you did this -> P-47D-27 = 0.0256 * 25.87 = 0.662272 (i assume your using 25.87 for wing area)

(i.e., use 1 instead of .0256 and 1 for speed since same for both planes and 2 for weight p47 and 1 for weight of 190)

27.87/2 (p47) or 18.3/1 (190) is bigger??? The latter is bigger, and since it is a subtraction from this gXcos(60), wing area and/or differences in zero drag coeff may be the deciding factor in the calculation of dive acceleration, not the weight. And if this is the case, dive acceleration is less for 190 than p47. Sorry,if this is confusing. It's late here.

Last edited by MadBlaster; 05-12-2012 at 06:14 AM.
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  #2  
Old 05-12-2012, 07:21 AM
BlackBerry BlackBerry is offline
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Quote:
Originally Posted by MadBlaster View Post
hmm, before I read further, I think we need zero lift drag coefficient for 190 to say that weight is the deciding factor. wiki says 27.87 m² for p47 wing area and 18.30 m² for 190A. Agree with you that denominator (i.e., weight) is almost twice as large for p47 verses 190, but numerator? To keep simple math, assume zero drag coeff=1 for both planes, 190 weighs "1" and p47 weighs "2" (weight on relative basis to each other). Then drag coefficient portion of numerator

-dragcoefficentX(speed)^2/weight

where you did this -> P-47D-27 = 0.0256 * 25.87 = 0.662272 (i assume your using 25.87 for wing area)

(i.e., use 1 instead of .0256 and 1 for speed since same for both planes and 2 for weight p47 and 1 for weight of 190)

27.87/2 (p47) or 18.3/1 (190) is bigger??? The latter is bigger, and since it is a subtraction from this gXcos(60), wing area and/or differences in zero drag coeff may be the deciding factor in the calculation of dive acceleration, not the weight. And if this is the case, dive acceleration is less for 190 than p47. Sorry,if this is confusing. It's late here.
27.87/2=13.93 much smaller than 18.3, so P47 has smaller subtraction from this g*cos(60).


BTW, this link says VDM 3m diametre has a 0.54 prop reduction gearing. Fw190A8 :VDM 9-12176A10 ft, 11 ¾ in. diameter 390 lbs

BMW-801D 2700rpm



Quote:
FockeWulf190BMW 801D radialVDM prop mechanism was built into the nose case of the engine itself, along with 1.72 to 1 cooling fan drive, 0.54 prop reduction gearing, magneto, oil pump, and front camshaft drive.

http://www.enginehistory.org/Convent...20Electric.pdf
So in 1943's test, @10000ft ,250mph IAS, fw190A4's propeller tip speed=(254^2+130^2)^0.5=286m/s=0.87Mach, less than 0.95 Mach of P47's.

Some P47's has 16:9 reduction which provides higher Mach number (1.05Mach ).

In conclusion, My opinion is that when p47 and fw190a4 at full engine 2700rpm dive from @10000ft ,250mph IAS, fw190's tip speed is about 0.87mach while p47's is around 0.945-1.05 Mach. Probably at that time P47's propeller's efficiency is quite lower than fw190, so p47 was outdove rapidly at initial diving stage.
111.JPG

Last edited by BlackBerry; 05-12-2012 at 07:31 AM.
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  #3  
Old 05-12-2012, 09:18 AM
MadBlaster MadBlaster is offline
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Your conclusion seems reasonable to me. I was digging into that hamilton clark link, it says the machs for best efficiencies were in the .7-.9 range. I would assume that plays out at cruising speeds.
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  #4  
Old 05-12-2012, 12:59 PM
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Crumpp Crumpp is offline
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Wow, it's seems that P47's designer just want to make the tip speed approach sonic as soon as posssible. Why?
4 meter diameter compared to a 3 meter diameter....

4 meters is a big prop and they have to push the tip speeds. Keep in mind, diameter is the most important factor in propeller design.

Good design can compensate, though.

Quote:
it says the machs for best efficiencies were in the .7-.9 range.
They were not dumb at Republic!


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This is probably the reason why P47 was outdived by fw190G from 250 mph(initial diving stage).
I did not check over your math but your final conclusion is absolutely right.
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  #5  
Old 05-12-2012, 03:47 PM
BlackBerry BlackBerry is offline
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Crumpp, thank your comments,I think I've found the answer! the NACA report of Hamilton standard tells us everything:1350rpm propeller 13ft diameter CSP just like P47's with the exception of 3-blade vs 4-blade.

http://digital.library.unt.edu/ark:/...etadc62146/m1/

There were two airfoil being tested, Clark Y airfoil was before WWII, not laminar. NACA16 was during WWII, NACA16 airfoil is laminar flow profile, and the test shows that there is no advantage of NACA16 airfoil when propeller's tip speed is 1Mach and when "advance ratio" is above 2.0, but there is no more than 3% efficiency benefit from NACA16 when "advanc ratio" is between 1.2 and 2.0.

advance ratio= TAS/(rpm*diameter)

fw190:3 meter propeller, 1400 rpm
p47d: 4 meter propeller, 1400 rpm

You can see Figure 24, when tip speed is 1 Mach, the more advance ratio, the lower efficiency. So we now come to know why Repulic engineer wanted as big propeller as possible because they wanted smaller advance ratio! When fw190 and P47 dive to same high TAS, the P47 has smaller advance ratio and higher efficiency AS LONG AS BOTH PROPELLER'S TIP SPEED IS AROUND 1 MACH. Republic engineers were right: since high TAS diving(efficiency loss)is inevitable for P47, why not prefer low "advance ratio" while accepting the high mach number of 4 meters big propeller's tip?

The complete formular of diving 65 degree is below:

acceleration=g*cos(65)-dragcoefficent*(TAS)^2/weight+Propellerthrust/weight

A simple math question: if you are P4D7's pilot fighting against a fw190G(both arr 250mph TAS @10000ft ), how can you get higher dive acceleration? On the right of formular there are three parts:

1) g*cos(65)
You have nothing to do with it, every a/c shares same value.

2) dragcoefficent*(TAS)^2/weight

Your huge weight is your advantage, and the bigger TAS, the more important role this part plays. So you should build up speed ASAP.

3) Propellerthrust/weight

Unfortunately the third part is your enemy's advantage. Although P47's efficiency is almost same as fw190's, your huge weight is your shortcoming.The NACA report says when tip speed is above 0.9 mach, the drag coefficient of tip increase rapidly, and when tip speed is 1.0 mach and advance ratio is above 2.0, the efficiency of propeller drops sharply. @250 IAS ,p47's advance ratio is about 1.32, not high, but as speed slightly building up, efficiency drops quicker than 0.5-0.8 Mach curve.

http://digital.library.unt.edu/ark:/...dc62146/m1/43/
http://digital.library.unt.edu/ark:/...dc62146/m1/13/
http://digital.library.unt.edu/ark:/...dc62146/m1/11/

You are now 250mph TAS @10000ft, your tip speed is 1 mach, and you will suffer from compressibility loss while your enemy dose NOT. The fw190 has more thrust than you, his weight is less than you, therefore his thrust/weight is much greater than you so that he can overcome your advantage----the second part of formular.

What should you do ? The answer is very simple and as same as the conclusion we've got from 2nd part of formular:

BUILD UP SPEED ASAP.

Drag him down!!! Yes, your tip speed will be always above 1 mach but now fw190's is also around 1 mach, he is now suffering from compressibility just like you, furthermore, his advance ratio(J) will much bigger than you, so his propeller efficiency drops more sharply than you. Now, the third part of formular is NOT enemy's advantage any more. You've succeded in eliminating his advantage and retaining and enlarging yours.

Congratulations from Republic engineers! You now have energy advantage by diving to high TAS, you are extending your distant now, do what you want to do.

The last thing is that if il2 4.11 models the compressibility loss of propeller efficiency . If not, there are 2 probem with its FM.

1) every piston a/c dives faster than it shoud be @ high TAS.

2)For those a/c like P47, the advantage of high TAS diving acceleration has been ignored, so is it's Low TAS diving accelaration shortcoming.

Now we can perfectly explain the fact of 1943 Dec test between fw190G and P47D, and many other comparation such as spitfire vs bf109 initial and final diving difference.

BTW, it's stupid for P47 to dive in a shallow angle with zeke which demonstrates the 6 ton thunderbolt has only a littile advantage(100yards)to the "kite"----Zeke52. I can image those angry faces of the Republic's engineers.


As for P51d, He has similar high TAS diving acceleration with P47, but the reason is not much depending on huge weight, it is very low coefficient of laminar wing. pls look at 2nd part of formular.

Last edited by BlackBerry; 05-12-2012 at 06:00 PM.
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  #6  
Old 05-12-2012, 05:11 PM
MadBlaster MadBlaster is offline
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about this part of the equation, Propellerthrust/weight ->

Simply lower the rpms to bring the p47 tips speeds down to optimal range .7-.9? Won't that give you better acceleration? It seems to work that way in game. Starting at 250 mph, full throttle, and 100% pp, nose trim 2 notches down, rads closed. if I nose it down into dive and crank down the prop pitch to 0% quickly and then bring it back up to ~77% and gradually lower throttle to about 77% in a dive from 250 mph, the planes gets to ~ 400 mph ias very quickly.
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Old 05-12-2012, 06:08 PM
BlackBerry BlackBerry is offline
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Quote:
Originally Posted by MadBlaster View Post
about this part of the equation, Propellerthrust/weight ->

Simply lower the rpms to bring the p47 tips speeds down to optimal range .7-.9? Won't that give you better acceleration? It seems to work that way in game. Starting at 250 mph, full throttle, and 100% pp, nose trim 2 notches down, rads closed. if I nose it down into dive and crank down the prop pitch to 0% quickly and then bring it back up to ~77% and gradually lower throttle to about 77% in a dive from 250 mph, the planes gets to ~ 400 mph ias very quickly.

Yes, that works. But even you can get same propeller efficiency as 190, your weight is too great to overcome, Propellerthrust/weight is still inferior to 190's.

We need to know if 190's airscrew tip compressibility loss is modelled or not at high mach number where 190's huge "advance ratio" making efficiency even worse than P47's.

Last edited by BlackBerry; 05-12-2012 at 06:11 PM.
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