4.11 F4U Performance

[MadBlaster]

okay, here's rough calculation for 18 knots. you can do same for 20 knots if you want. pulling data from my other post:

go to page 60 (manual not pdf#) of that link. look at the chart for gross weight 13100 lb for takeoff on a hard surface. notice that you need 380 feet with a 30 knot headwind or 680 feet with a 15 knot headwind.

So for 18 knot, to figure required distance from the chart data:
680 ft-380ft=300 ft (distance differential)
30 knot-15 knot=15 knot (headwind differential)
300 ft /15knot = 20 ft/knot (relate the two differential)
18 knot-15 knot = 3 knot (18 knots is what we knot, not 15 knots...he, he another one)

3knot*20ft/knot = 60 ft
680 ft-60ft ~ 620 feet needed at 18 knots.
Casablanca is 512 ft, so too short at 18 knots.

[F19_Klunk]

again..For me discussing the take off length in irrelevant as it seems that catapult was used both on Essex class carriers and escort carriers...
Too bad it's not modeled. If it was we wouldn't discuss takeoff but rather the rest of the FM.