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#1
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center of gravity....or your stick must have an equal length/width/depth.....i.e. is a cube shaped stick.......simples
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Intel Q9550 @3.3ghz(OC), Asus rampage extreme MOBO, Nvidia GTX470 1.2Gb Vram, 8Gb DDR3 Ram, Win 7 64bit ultimate edition |
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#2
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more surface tension if it floats horizontally...
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#3
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...ditto, what they said...
Last edited by retrojet; 10-09-2011 at 12:35 AM. Reason: I got no idea... |
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#4
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if this doesnt confuse you as it confuses me well....
im sorry your critic spirit got killed by the educative syustem ![]() FROM WHERE DOES IT GET THE ENERGY TO GO FROM ONE POSITION TO OTHER¡¡¡¡
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
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#5
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Why have you put the CoG on the waterline?
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Intel Q9550 @3.3ghz(OC), Asus rampage extreme MOBO, Nvidia GTX470 1.2Gb Vram, 8Gb DDR3 Ram, Win 7 64bit ultimate edition |
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#6
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because it has density = o.5 so it floats exactly in the midle
thanks for listening litle grasshoper
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
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#7
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ok genious.....what about the half thats under water.....it will still want to 'float' so it will turn itself until it reaches some sort of stability....i.e. it will lay itself flat
__________________
Intel Q9550 @3.3ghz(OC), Asus rampage extreme MOBO, Nvidia GTX470 1.2Gb Vram, 8Gb DDR3 Ram, Win 7 64bit ultimate edition |
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#8
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exactly you got it but water spends energy lowering the level of it or moving the stick cog
but neither happens an isentropic work in nature? edit: so maybe you agree that in both cases the force of the water on the stick aint the same?
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL Last edited by raaaid; 10-09-2011 at 03:39 PM. |
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