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Hello whiskey-charlie,
I am not member of the Team Daidalos but I think I can at least answer your first question. I assume that we talk about aviation gasoline (AvGas 80, 82UL, 91, 100LL, 100), and this fuel has, depending on what kind of fuel it actually is, a density between 0.73Kg/L and 0.78Kg/L at 15°C (lets use the average of 0.755Kg/L). physics teaches us: density = mass/volume (ρ = m/V) -> V = m/ρ With a given fuel-load of, lets say 100Kg of aviation gasoline, we now have: volume V = Mass m / density ρ volume V = 100Kg / 0.755KG/L ≈ 132.45 Liter There are two different gallons in use, the Imperial Gallon (4.54609 Liter) and the US Liquid Gallon (3.785411784 Liter). I assume IL-2 uses the US liquid gallon, Team Daidalos, can you confirm that? OK, 100Kg of AvGas have a volume of 132.45 Liter, and that is (assuming it is US liquid gallons): 1 US Liquid Gallon = 3.785411784 Liter -> 1 Liter = 1 / 3.785411784 US liq. gallons -> 132.45 Liter = 132.45 / 3.785411784 ≈ 34.99 US liq. gallons -------------------------------------------------------------------------- I can only guess what the answer to your second question might be... I think the oil-in and oil-out temperatures refer to the oil-temperature before the oil enters the oil-cooling device and its temperature when it leaves the cooling-device OR its temperature before it enters and after it leaves the engine. Only these two cases make any sense to me... so you could test it: Is oil-in temperature higher than oil-out temperature? -> temp. before and after cooling device. Is oil-in temperature lower than oil-out temperature? -> temp. before and after engine. Hope I could help a bit, Daedalus Last edited by FS~Daedalus; 04-19-2012 at 10:53 AM. |
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