why didnt i study this in five years of thermodinamics

[raaaid]

well outlaw so you belive i did study thermo, check this out:

http://energy.sdsu.edu/testhome/Test...C/TSatR12.html

the vapur pressure differnce bewteen top and bottom with a gradient of five degrees its 100 kpa

this means the wheel can work with 10 m diametrum on a 5 º gradient

how much work is that for kg of r12?

1*10*10=100 J

whats the internal energy difference for 5 º
around 5 J/kg

U variation=Q-W
5=Q-100

Q=105

eficiency=w/q=100/105=95% eficiency

negelcting a ten percent of mechanical lost it gives the 85% figure matching the claimed author eficiency

if it filtered to the wiki is cause things are changing due to the 2012 effect of next leap of evolution