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#1
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i learnt small basic to study probability in order to find a way to beat the casino and i made this interesting disocovery
if you take a long string of decimal numbers the string 123 will apeear every 1000 digits while the 221 every 995 digits this small basic program proves it start: TextWindow.WriteLine( digitcount/twotwoone) a= Math.GetRandomNumber(10) digitcount= digitcount+1 If a=2 Then Goto seconddigit Else Goto start EndIf seconddigit: a= Math.GetRandomNumber(10) digitcount= digitcount+1 If a=2 Then Goto thirddigit Else Goto start EndIf thirddigit: a= Math.GetRandomNumber(10) digitcount= digitcount+1 If a=2 Then Goto thirddigit EndIf If a=1 Then Goto bingo EndIf If a<>1 And a<>2 Then Goto start EndIf bingo: twotwoone= twotwoone+1 Goto start so for example in the roulete is much more likely to appear the combination 2nd,2nd,1st column than 1st,2nd,3rd column i love these kind of problems either they keep you entertained for the rest of your life or hav a huge victory ![]()
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
#2
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Selecting random digits from 0 to 9 inclusive, the probability of getting a 1-2-3 combination (in that order) is: 1/10 x 1/10 x 1/10 = 1/1000
Selecting random digits from 0 to 9 inclusive, the probability of getting a 2-2-1 combination (in that order) is: 1/10 x 1/10 x 1/10 = 1/1000 Your statement that "so for example in the roulete is much more likely to appear the combination 2nd,2nd,1st column than 1st,2nd,3rd column", is incorrect for 2 reasons: 1. Firsly, it is not correct to say that a probability of 1/995 is 'much more likely' than a probability of 1/1000. Statistically speaking these probability values are virtually identical. 2. Your result of a probability of 1/995 for a number string of 2-2-1 being different from 1/1000 for number string 1-2-3 simply represents the natural randomness of your basic computer random function, and not a true statistical difference in probability. Simple probabilty theory (above) shows that the probabilty of getting a 1-2-3 is the same as the probability of getting a 2-2-1. Run your program again & again. You will get probabilty values for 2-2-1 combination very close to (but not not always exactly) 1/1000.
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When one engine fails on a two engine bomber, you will always have enough power left to get to the scene of the crash. Get the latest COD Team Fusion patch info HERE Last edited by salmo; 04-30-2012 at 12:26 PM. |
#3
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probability of getting 123 or 221 is equal IN A 3 DIGIT STRING
probability of getting 221 is bigger than getting 123 in A MILLION DIGIT STRING this is old and not really related but here as you can veryfy with your browser searcher number 21 appears(with the searcher rules) 10% more than number 11 check yourself dont just believe me http://www.eveandersson.com/pi/digits/1000000
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
#4
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even if you were right, it's a 5‰ difference, got luck exploiting it.
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#5
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oh i dont want no money just to prove eisntein wrong whom i dislike for being a psicological mistreateer
in fact quantum phisics expect a certain degree of nonlocality in cahnce as theres in space oh and thats a 0.5% difference
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
#6
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what you think the symbol "‰" stands for?
![]() and why einstein? |
#7
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oh i usually take accepted as imposible problems to solve for the fun
both my folks are mathematicians so have it on the genes i dont know i dont see eisntein as a role model, succesfull people pass to history as role models while they trully were sick persons another example of this is picasso a socialized psicho who influenced several women into suicide by making magic with art(if you rather a more rational aproach that is depicting them in a grotesque manner)
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
#8
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When one engine fails on a two engine bomber, you will always have enough power left to get to the scene of the crash. Get the latest COD Team Fusion patch info HERE Last edited by salmo; 04-30-2012 at 01:27 PM. |
#9
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i dont think chance is random either just unknown
you dont get the pi thing which makes 21 appear a 10% more than 11, a clue: number 21112 is two 11 or one 11? but the thing is that this is not appliable to 221 vs 123
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
#10
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I agree that the digits of pi throw up some rather interesting combinations, but you just cannot use these digit combinations to make a statements about probability of digit combinations from a random data set or a gambling table.
Your statements about statistical likelihood assumes that each trial (the selection of the next digit) is indepenent of all other trials, but this is not the case. The next trial (next digit selection) is dependent upon the previous digit in the sequence of Pi since any repention of Pi the nth decimal place is fixed and repeatable. I's be interested to see your results once you've repeated your analysis with a different (random) dataset.
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When one engine fails on a two engine bomber, you will always have enough power left to get to the scene of the crash. Get the latest COD Team Fusion patch info HERE |
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