Quote:
Originally Posted by TomcatViP
Storm, I think you are mixing convergence indication on the gunsight and guns convergence.
There is no way you can set your guns to converge as so short distance as 50 m. Try to remind that flying a fighter plane during BoB was not a sport that you will practice in a selfish manner. You had orders, directives and technical operatives procedures that order could be achieved following the directives (otherwise there is no planned tactics hence no strategies).
By the way, those indication are in the maintenance manuals, not in the pilot manual. I think I alrdy saw one passing by on this forum
You also made an error IMHO:
Distance of convergence = L*cosinus
Distance of gun from main axis = L*sinus
tan= sin/cos and Tan^-1=angle of EACH GUN
Offset of gun at the gun's breech : d_gun*sinus (d is the length of the buried part of the gun)
In the case of 50m conv for 2m it give us 8cm offset (1m long gun - machine-gun).
For a plane with four gun in each wing, it means that you'll have to keep 32cm of available free space without taking into account any structural spacer.
Also : Size of prop = 3.6 for 109 if I do remind well
etc...
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Actually that is exactly how I calculated the angle:
angle = arctan (convergence / distance of gun) (tangens = Gegenkathete durch Ankathete)
So assuming that the gun in question was about 2m from the symmetrical plane the difference of gun orientation in the horizontal plane would be merely 2° when passing from 100m to 50m convergence. 2° is nothing.
And Hartmann definitely shot at close range and he gave a dam about what the handbook or the rules said.
EDIT: For 2° the offset on the tip or the end of the buried part pf the gun would be 7 cm assuming a 2m gun length buried in the wing and assuming that the other end did not move. Assuming that the centre of the buried part did not move the spacing needed on both ends would be merely 3.5cm.