bingo, is this a pattern in chaos?
 

imagine youre playing bingo with two binary numbers and the numbers can repeat

you have the card with the numbers one and one and i have the card with the number 01

ill need on average four balls to win while you six, so at this game ill win 3 times for every two you win

this driving me crazier

is there any game like this since bingo truly is not for not having repeated numbers

Im not playing if your gonna win all the time raid... :(

oh i explained terribly bad ill try again

imagine i have lottery number 1111 and you have lottery number 1234

on a FOUR ball extraction we have identical chances

but if they keep extracting balls till that numbers reached i have much less chances with the number 1111

is there any game like this?

If duplicate balls are in the machine, how many balls are there in total? and how many duplicates of each ball? By the way you dont need to start a new paragraph for every sentence... It makes it hard to read.

see this is the formula to obtain how many times do you need to extrac a binary ball so it appears 1111 and you do till it appears so its undefined

you guess it from the expected succes of a martingale betting system vs the expected loses which is 1/2, every time the other option appears, you win every time it appears your option in a four row when you win 16 minus the one you bet

so the formula to obtain how many times you have to play to obtain 1111 is:

((2^4)-1)/x=1/2

so 1111 will appear every 30 times while 0101 every 16

its got to be this way or you could win in a casino but who knows maybe theres a way to win

what i wonder is if someone designed a game thinking that in a bingo with repeated numbers there the same chance to get number ten than eleven which would be badly bdaly flwaed and would allow for 25% edges in your favour

Maybe this is why they use more than 2 numbers for gambling Raid... So you dont win allot... ;)